Matematică
tagirtamadalina
2015-11-16 12:07:09
Ma puteti ajuta? Va rog :)
Răspunsuri la întrebare
Cont şters
2015-11-16 14:01:41

a) =2x|√3-2|-x|√3+2|+3x|1-√3|= =2x(2-√3)-x(√3+2)+3x(√3-1)= =4x-2√3x-√3x-2x+3√3x-3x= =-x-3√3x+3√3x= =-x b) 2xy|2√3-3|+xy|2√3-4|-2√3xy= =2xy(2√3-3)+xy(4-2√3)-2√3xy= =4√3xy-6xy+4xy-2√3xy-2√3xy= =4√3xy-2xy-4√3xy= =-2xy c) =x^2|2-√3|+x^2|3-2√3|-x^2|1-√3|= =x^2(2-√3)+x^2(2√3-3)-x^2(√3-1)= =2x^2-√3x^2+2√3x^2-3x^2-√3x^2+x^2= =-2√3x^2+2√3x^2-x^2+x^2= =0

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