(2+3i)/(3-2i) (2+3i)(3+2i)/9-4i^2 6+4i+9i+6i^2/9+4 6-6+13i/13 =i.=> partea reala=0.

[latex]z= frac{2+3i}{3-2i} = frac{(2+3i)(3+2i)}{(3-2i)(3+2i)} = frac{6+13i+6i^2}{9-4i^2} = frac{13i}{13}=i=0+1i\ Rez=0 \ Imz=1[/latex]