Matematică
antoniobraga20
2015-11-10 03:54:54
Sa se imparta numarul 1200 in parti invers proportionale cu : 5/4; 5/3; 5/12; 5/6
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Mashaa
2015-11-10 05:26:26

5a/4=k    a=4k/5 5b/3=k    b=3k/5 5c/12=k  c=12k/5 5c/6=k    d=6k/5 a+b+c+d=1200 4k/5+3k/5+12k/5+6k/5=1200 25k/5=1200 5k=1200 k=1200/5=240 a=4k/5=4×240/5=192 b=3k/5=3×240/5=144 c=12k/5=12×240/5=576 d=6k/5=6×240/5=288

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