Matematică
irinamiu
2015-11-12 10:00:24
{[(x+3)•3+3]•3+3}:3+4=20
Răspunsuri la întrebare
Alinut12
2015-11-12 16:04:38

{[(x+3)•3+3]•3+3}:3+4=20 {[(x+3)•3+3]•3+3}:3=20-4 {[(x+3)•3+3]•3+3}:3=16 [(x+3)•3+3]•3+3=16×3 [(x+3)•3+3]•3+3=48 [(x+3)•3+3]•3=48-3 [(x+3)•3+3]•3=45 (x+3)•3+3=45:3 (x+3)•3+3=15 (x+3)•3=15-3 (x+3)•3=12 x+3=12:3 x+3=4 x=4-3 x=1 Bafta!! :3

Alexandrucondrea
2015-11-12 16:05:53

[latex]Big{ig[( ext{x}+3)cdot3+3ig]cdot3+3Big}:3+4=20\ \ Big{ig[( ext{x}+3)cdot3+3ig]cdot3+3Big}:3 = 20-4 \ \ {ig[( ext{x}+3)cdot3+3ig]cdot3+3Big}:3 = 16 $ $\ \ ig[( ext{x}+3)cdot3+3ig]cdot 3+3 = 16cdot 3 \ \ig[( ext{x}+3)cdot3+3ig]cdot3+3 = 48 \ \ ig[( ext{x}+3)cdot3+3ig]cdot3 = 48-3 \ \ig[( ext{x}+3)cdot3+3ig]cdot3 = 45 \ \ ( ext{x}+3)cdot3+3 = 45:3 \ \ ( ext{x}+3)cdot3+3 = 15 \ \ ( ext{x}+3)cdot3 = 15-3[/latex] [latex]( ext{x}+3)cdot3 = 12 \ \ ext{x}+3 = 12:3 \ \ ext{x}+3 = 4 \ \ ext{x} = 4-3 \ \ oxed{ ext{x} = 1} [/latex]

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